# SAT/ACT problem of the week, September 29, 2016 solution

Hint for process of elimination: Though this problem has a “None of the above” option, choosing a random value for \$latex z &s=1\$ satisfying the simple conditions that \$latex z &s=1\$ is odd, such as \$latex z=3 &s=1\$, would immediately eliminate three of the choices because the answers are odd.

A second benefit of choosing a random value of \$latex z &s=1\$ is that the process may increase your intuition of what the answer should be.

Read on for a full solution.

# SAT problem of the week, September 29, 2014

If \$latex z &s=1\$ is an odd integer, which of the following is an even integer?

1. \$latex z+2 &s=1\$ (check answer)
2. \$latex z-2 &s=1\$ (check answer)
3. \$latex z^2 – 3z &s=1\$ (check answer)
4. \$latex (z+2)(z-2) &s=1\$ (check answer)
5. None of the above (check answer)

Solutions, hints, and questions are welcomed. A full solution will be posted on October 5th. If you would like to learn how to enter math formulas into this blog, visit the WordPress LaTeX tutorial page.

# SAT problem of the week, September 29, 2014 solution

Hint for process of elimination: Though this problem has a “None of the above” option, choosing a random value for \$latex z &s=1\$ satisfying the simple conditions that \$latex z &s=1\$ is odd, such as \$latex z=3 &s=1\$, would immediately eliminate three of the choices because the answers are odd.

A second benefit of choosing a random value of \$latex z &s=1\$ is that the process may increase your intuition of what the answer should be.

Read on for a full solution.