**Hint for process of elimination: **Though this problem has a “None of the above” option, choosing a random value for $latex z &s=1$ satisfying the simple conditions that $latex z &s=1$ is odd, such as $latex z=3 &s=1$, would immediately eliminate three of the choices because the answers are odd.

A second benefit of choosing a random value of $latex z &s=1$ is that the process may increase your intuition of what the answer should be.

Read on for a full solution.