Hint for process of elimination: Though this problem has a “None of the above” option, choosing a random value for $latex z &s=1$ satisfying the simple conditions that $latex z &s=1$ is odd, such as $latex z=3 &s=1$, would immediately eliminate three of the choices because the answers are odd.
A second benefit of choosing a random value of $latex z &s=1$ is that the process may increase your intuition of what the answer should be.
Read on for a full solution.
If $latex z &s=1$ is an odd integer, which of the following is an even integer?
- $latex z+2 &s=1$ (check answer)
- $latex z-2 &s=1$ (check answer)
- $latex z^2 – 3z &s=1$ (check answer)
- $latex (z+2)(z-2) &s=1$ (check answer)
- None of the above (check answer)
Solutions, hints, and questions are welcomed. A full solution will be posted on October 5th. If you would like to learn how to enter math formulas into this blog, visit the WordPress LaTeX tutorial page.